Class 12 Chemistry MCQs are very important for students who want to score good marks in their CBSE HBSE RBSE board examination. These Chemistry MCQs are also helpful for students preparing for NEET/JEE exams. Students who can Practice CBSE Class 12 Chemistry Multiple Choice Questions with Answers to improve your score in all Chemistry competitive and Board Exam
Class 12 The Solid State MCQs with Answers
Q1.Silicon doped with electron-rich impurity forms __.
- p-type semiconductor.
- n-type semiconductor.
- Intrinsic semiconductor.
- Insulator
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Ans: 1. n-type semiconductor
Explanation:
When silicon is doped with electron rich impurity like P or As, the increase in conductivity is due to the negatively charged Electron.
Hence, silicon doped with electron rich impurity is termed as ‘n-type semiconductor’
Q2. Amorphous solid can also be called __.
- Pseudo solids.
- True solids.
- Super cooled liquids.
- Super cooled solids.
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Ans: 1. Pseudo solids.
2. Super cooled liquids
Q3. Which of the following statements are true about semiconductors?
- Silicon doped with electron rich impurity is a p-type semiconductor.
- Silicon doped with an electron rich impurity is an n-type semiconductor.
- Delocalised electrons increase the conductivity of doped silicon.
- An electron vacancy increases the conductivity of n-type semiconductor
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Ans: 2. Silicon doped with an electron rich impurity is an n-type semiconductor
Q4. In which of the following structures coordination number for cations and anions in the packed structure will be
same?
- Cl– ion form fcc lattice and Na ions occupy all octahedral voids of the unit cell.
- Ca2- ions form fcc lattice and F ions occupy all the eight tetrahedral voids of the unit cell.
- O2- ions form fcc lattice and Na ions occupy all the eight tetrahedral voids of the unit cell.
- S2- ions form fcc lattice and Zn ions go into alternate tetrahedral voids of the unit cell.
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Ans: 1. Cl– ion form fcc lattice and Na ions occupy all octahedral voids of the unit cell.
Q5. Which of the following solids is not an electrical conductor?
- Mg (s).
- TiO (s).
- I2 (s).
- H2O (s).
- (A) only.
- (B) Only.
- (C) and (D).
- (B), (C) and (D).
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Ans: 3. (C) and (D).
Q6. Schottky defect is observed in crystals when __.
- Some cations move from their lattice site to interstitial sites.
- Equal number of cations and anions are missing from the lattice.
- Some lattice sites are occupied by electrons.
- Some impurity is present in the lattice.
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Ans: 2. Equal number of cations and anions are missing from the lattice.
Q7. The lattice site in a pure crystal cannot be occupied by _.
- Molecule.
- Ion.
- Electron.
- Atom.
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Ans: 3. Electron.
Explanation:
Pure crystals have constituents i.e., atoms or molecules or ions as lattice points which are arranged in fixed stoichiometric ratio.
Electron can occupy the lattice site only when there is imperfection in solid and not in a pure crystal.
Hence, existence of free electrons are not possible, it is possible on in case of imperfection in solid.
Q8. Which of the following statements are correct?
- Ferrimagnetic substances lose ferrimagnetism on heating and become paramagnetic.
- Ferrimagnetic substances do not lose ferrimagnetism on heating and remain ferrimagnetic.
- Antiferromagnetic substances have domain structures similar to ferromagnetic substances and their
magnetic moments are not cancelled by each other. - In ferromagnetic substances all the domains get oriented in the direction of magnetic field and remain as
such even after removing magnetic field.
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Ans: 1. Ferrimagnetic substances lose ferrimagnetism on heating and become paramagnetic.
- In ferromagnetic substances all the domains get oriented in the direction of magnetic field and remain as such even after removing
magnetic field.
Q9. The value of magnetic moment is zero in the case of antiferromagnetic substances because the domains
__.
- Get oriented in the direction of the applied magnetic field.
- Get oriented opposite to the direction of the applied magnetic field.
- Are oppositely oriented with respect to each other without the application of magnetic field.
- Cancel out each other’s magnetic moment.
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Ans: 3. Are oppositely oriented with respect to each other without the application of magnetic field.
- Cancel out each other’s magnetic moment.
Q10. In which of the following arrangements octahedral voids are formed?
- hcp.
- bcc.
- Simple cubic.
- fcc.
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Ans: 1. hcp
4. fcc.
Q11. Which of the following defects decrease the density?
- Interstitial defect.
- Vacancy defect.
- Frankel defect.
- Schottky defect.
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Ans: 2. Vacancy defect.
- Schottky defect
Q12. Which of the following is a network solid?
- SO2 (Solid).
- I2 .
- Diamond.
- H2O (Ice).
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Ans: 1. Diamond.
Q13. Graphite is a good conductor of electricity due to the presence of __.
- Lone pair of electrons.
- Free valence electrons.
- Cations.
- Anions.
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Ans: 2. Free valence electrons.
Explanation:
In graphite one carbon atom is attached to three other carbon atoms. One electron of carbon remains free. Due to this free valence
electron graphite is an electrical conductor
Q14. The number of tetrahedral voids per unit cell in NaCl crystal is __.
- 4
- 8
- Twice the number of octahedral voids.
- Four times the number of octahedral voids.
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Ans: 2. 8
- Twice the number of octahedral voids.
Explanation:
The number of tetrahedral voids per unit cell in NaCl is calculated as:
Since NaCl has fcc lattice.
No. of atoms (n) per unit cell = 4
No. of octahedral void = n = 4
No. of tetrahedral void= 2n = 2 × 4 = 8
This confirms answer at options (ii) and (iii), both
Q15. Which of the following cannot be regarded as molecular solid?
- SiC (Silicon carbide).
- AlN.
- Diamond.
- I2 .
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Ans: 1. SiC (Silicon carbide).
- AlN.
- Diamond.
Explanation:
SiC (Silicon carbide), AlN, and diamond are not regarded as molecular solids. They are grouped separately as covalent or network
solids.
Q17. The percentage of empty space in a body centred cubic arrangement is __.
- 74
- 68
- 32
- 26
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Ans: 3. 32
Explanation:
Packing efficiency for bcc arrangement is 68% which represents total filled space in the unit cell. Hence, empty space in a body
centered arrangement is 100 – 68 = 32%.
Q18. Graphite cannot be classified as __.
- Conducting solid.
- Network solid.
- Covalent solid.
- Ionic solid.
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Ans: 4. Ionic solid.
Explanation:
Graphite is a covalent or Network solid, therefore it cannot be grouped as an ionic solid.
Q19. In which pair most efficient packing is present?
- hcp and bcc.
- hcp and ccp.
- bcc and ccp.
- bcc and simple cubic cell.
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Ans: 2. hcp and ccp.
Explanation:
In hcp and ccp the packing efficiency is maximum (i.e. 74%), hence this pair of packing is considered as “most efficient packing”.
Q20. Which of the following statements is not true?
- Paramagnetic substances are weakly attracted by magnetic field.
- Ferromagnetic substances cannot be magnetised permanently.
- The domains in antiferromagnetic substances are oppositely oriented with respect to each other.
- Pairing of electrons cancels their magnetic moment in the diamagnetic substances.
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Ans: 2. Ferromagnetic substances cannot be magnetised permanently.
Q21. The correct order of the packing efficiency in different types of unit cells is ________.
1. fcc < bcc < simple cubic.
2. fcc > bcc > simple cubic.
3. fcc < bcc > simple cubic.
4. bcc < fcc > simple cubic.
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Ans: 1. fcc > bcc > simple cubic.
Q22. To get a n-type semiconductor from silicon, it should be doped with a substance with valence __.
- 2
- 1
- 3
- 5
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Ans: 4. 5
Explanation:
Impurity of higher group is doped to get n-type semiconductor. Thus, silicon (valency = 4) should be doped with the element with
valency equal to 5.
Q23. Which of the following statements are not true?
- Vacancy defect results in a decrease in the density of the substance.
- Interstitial defects results in an increase in the density of the substance.
- Impurity defect has no effect on the density of the substance.
- Frankel defect results in an increase in the density of the substance.
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Ans: 3. Impurity defect has no effect on the density of the substance.
- Frankel defect results in an increase in the density of the substance.
Q24. Which of the following oxides shows electrical properties like metals?
- SiO2 .
- MgO.
- SO2 (s).
- CrO2 .
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Ans.4.CrO2.
Q25. Frenkel defect is also known as __.
- Stoichiometric defect.
- Dislocation defect.
- Impurity defect.
- Non-stoichometric defect.
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Ans: 1. Stoichiometric defect.
- Dislocation defect.
Explanation:
In Frenkel defect, dislocation of cations takes place and there is no change in stoichiometry of the crystal.